A) 1 : 1
B) 1 : 2
C) 2:1
D) None of these
Correct Answer: A
Solution :
\[Zn+{{H}_{2}}S{{O}_{4}}\to ZnS{{O}_{4}}+{{H}_{2}}\uparrow \] \[Zn+2NaOH\to N{{a}_{2}}Zn{{O}_{2}}+{{H}_{2}}\uparrow \] Both the balanced equations show that from equal amount of zinc, both \[{{H}_{2}}S{{O}_{4}}\] and \[NaOH\] will liberate same amount of hydrogen.You need to login to perform this action.
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