A) 96
B) 34
C) 10
D) \[2\sqrt{2}\]
Correct Answer: B
Solution :
(b): \[x=\frac{\sqrt{2}+\sqrt{1}}{\sqrt{2}-\sqrt{1}}\times \frac{\sqrt{2}+\sqrt{1}}{\sqrt{2}+\sqrt{1}}\] \[\frac{{{\left( \sqrt{2}+\sqrt{1} \right)}^{2}}}{2-1}\] \[\Rightarrow x=2+1+2\sqrt{2}\Rightarrow x=3+2\sqrt{2}\] And similarly \[y=3-2\sqrt{2}\] \[{{x}^{2}}+{{y}^{2}}={{\left( x+y \right)}^{2}}-2xy={{\left( 6 \right)}^{2}}-2(9-8)=34\]You need to login to perform this action.
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