A) 49
B) 34
C) 100
D) 102
Correct Answer: B
Solution :
(b): \[b=\frac{1}{a}=\frac{1}{3+2\sqrt{2}}=3-2\sqrt{2}\] \[\therefore \,\,{{a}^{2}}+{{b}^{2}}={{(3+2\sqrt{2})}^{2}}+{{(3-2\sqrt{2})}^{2}}\] \[=2({{3}^{2}}+{{(2\sqrt{2})}^{2}}=34\]You need to login to perform this action.
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