A) 8
B) 2
C) 16
D) 4
Correct Answer: A
Solution :
(a): \[A\times B\times C={{2}^{x}}\times {{4}^{y}}\times {{8}^{z}}\] \[\Rightarrow {{2}^{x}}\times {{2}^{y}}\times {{2}^{3x}}\] \[\Rightarrow {{2}^{\left( x+2y+3z \right)}}\Rightarrow {{2}^{\left( \frac{1}{9}+\frac{8}{9}+\frac{18}{9} \right)}}\] \[\Rightarrow {{2}^{3}}=8\]You need to login to perform this action.
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