A) \[\frac{1}{4}\]
B) \[\frac{1}{3}\]
C) \[\frac{1}{2}\]
D) \[\frac{1}{5}\]
Correct Answer: A
Solution :
(a): \[x=2+\frac{3}{9}-1=\frac{3}{2}\] \[y=2+\frac{5}{9}-\frac{5}{9}=2\] \[\therefore {{x}^{2}}+{{y}^{2}}-2xy=\frac{9}{4}+4-2.3\times 2\] \[\frac{1}{4}\]You need to login to perform this action.
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