A) \[[a,\,a({{t}_{1}}+{{t}_{2}}+{{t}_{3}}+{{t}_{1}}{{t}_{2}}{{t}_{3}})]\]
B) \[[-a,a\,({{t}_{1}}+{{t}_{2}}+{{t}_{3}}+{{t}_{1}}{{t}_{2}}{{t}_{3}})]\]
C) \[[-a\,({{t}_{1}}+{{t}_{2}}+{{t}_{3}}+{{t}_{1}}{{t}_{2}}{{t}_{3}}),\,a]\]
D) None of these
Correct Answer: B
Solution :
\[\Rightarrow \,\,8\,({{x}^{2}}+{{y}^{2}})-36y-2x+35=0\] Therefore, perpendicular from point third \[{{t}_{2}}x+y=a[{{t}_{1}}{{t}_{2}}{{t}_{3}}+{{t}_{1}}+{{t}_{3}}]\]and perpendicular from point first \[{{t}_{3}}x+y=a[{{t}_{1}}{{t}_{2}}{{t}_{3}}+{{t}_{1}}+{{t}_{2}}]\] \[x=-a,y=a[{{t}_{1}}{{t}_{2}}{{t}_{3}}+{{t}_{1}}+{{t}_{2}}+{{t}_{3}}]\].
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