A) (- 33, -26)
B) (33, 26)
C) (26, 33)
D) None of these
Correct Answer: B
Solution :
Let third vertex be (h, k). Now slope of AD is \[\frac{k-2}{h-1}\], Slope of \[BC\] is \[\frac{5+3}{-2-4}=\frac{-4}{3}\] Slope of BE is \[\frac{-3-2}{4-1}=\frac{-5}{3}\] And slope of AC is \[\frac{k-5}{h+2}\] Since \[AD\,\bot \,BC\Rightarrow \frac{k-2}{h-1}\times \frac{-4}{3}=-1\] \[3h-4k+5=0\] ......(i) Again Since \[BE\,\bot \,AC\Rightarrow -\frac{5}{3}\times \frac{k-5}{h+2}=-1\] Þ \[3h-5k+31=0\] .....(ii) on solving (i) and (ii) we get \[h=33,k=26\] Hence the third vertex is (33, 26).You need to login to perform this action.
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