A) 7.64 MeV
B) 76.4 MeV
C) 764 MeV
D) 0.764 MeV (\[{{e}^{-}}\]=0.00055 amu, \[p\]=1.00814 amu, \[n\]=1.00893 amu)
Correct Answer: A
Solution :
Mass of 6 neutrons = 6.05358 amu, Mass of 6 protons = 6.04884 amu, Mass of n + Mass of p =12.10242 amu Mass defect = 12.10242 ? 12.00710 = 0.09532 Binding energy = 0.09532 \[\times \] 931 = 88.74292 MeV. Binding energy per neucleon = 88.74292/12 =7.39 MeVYou need to login to perform this action.
You will be redirected in
3 sec