A) 1
B) 1/16
C) 1/4
D) 1/8
Correct Answer: B
Solution :
\[T={{t}_{1/2}}\times n,\] \ \[n=\frac{80}{20}=4\] Amount left \[=\frac{1}{{{2}^{n}}}=\frac{1}{{{2}^{4}}}=\frac{1}{16}\].You need to login to perform this action.
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