A) A.P.
B) G.P.
C) H.P.
D) None of these
Correct Answer: C
Solution :
\[x,\ 1,\ z\] are in A.P., then \[2=x+z\] ......(i) and \[4=xz\] ......(ii) Divide (ii) by (i), we get \[\frac{x\ .\ z}{x+z}=\frac{4}{2}\]or \[\frac{2xz}{x+z}=4\] Hence \[x,\ 4,\ z\] will be in H.P.You need to login to perform this action.
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