A) A.P.
B) G.P.
C) H.P.
D) None of these
Correct Answer: C
Solution :
Clearly \[x=\frac{1}{1-a},\ y=\frac{1}{1-b},\ z=\frac{1}{1-c}\] Since \[a,\ b,\ c\] are in A.P. \[\Rightarrow \] \[1-a,\ 1-b,\ 1-c\] are also in A.P. \[\Rightarrow \] \[\frac{1}{1-a},\ \frac{1}{1-b},\ \frac{1}{1-c}\]are in H.P. \[\therefore \]\[x,\ y,\ z\] are in H.P.You need to login to perform this action.
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