A) \[\pm \frac{2}{\sqrt{3}}\]
B) \[\pm \sqrt{3}\]
C) \[\pm \frac{\sqrt{3}}{2}\]
D) 0
Correct Answer: A
Solution :
Given that equation of curve \[y={{x}^{3}}=f(x)\] So \[f(2)=8\] and \[f(-2)=-8\] Now \[f'(x)=3{{x}^{2}}\Rightarrow f'(x)=\frac{f(2)-f(-2)}{2-(-2)}\] Þ\[\frac{8-(-8)}{4}=3{{x}^{2}};\,\,\,\,\therefore x=\pm \frac{2}{\sqrt{3}}\].You need to login to perform this action.
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