A) \[\left( \frac{7}{2},\frac{1}{2} \right)\]
B) \[\left( \frac{7}{2},\frac{1}{4} \right)\]
C) (1, 4)
D) (4, 1)
Correct Answer: B
Solution :
Let the point be \[({{x}_{1}},\,{{y}_{1}}).\] Therefore \[{{y}_{1}}={{({{x}_{1}}-3)}^{2}}\] ?..(i) Now slope of the tangent at \[({{x}_{1}},\,{{y}_{1}})\] is \[2({{x}_{1}}-3),\] but it is equal to 1. Therefore, \[2({{x}_{1}}-3)=1\Rightarrow {{x}_{1}}=\frac{7}{2}\] \[\therefore {{y}_{1}}={{\left( \frac{7}{2}-3 \right)}^{2}}=\frac{1}{4}\]. Hence the point is \[\left( \frac{7}{2},\frac{1}{4} \right)\].You need to login to perform this action.
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