A) 8.00
B) 5.25
C) 4.00
D) 6.25
Correct Answer: D
Solution :
\[f(x)=\sqrt{x}\] \[\therefore \,\,f(a)=\sqrt{4}=2,\] \[f(b)=\sqrt{9}=3\] ; \[{f}'(x)=\frac{1}{2\sqrt{x}}\] Also, \[{f}'(c)=\frac{f(b)-f(a)}{b-a}=\frac{3-2}{9-4}=\frac{1}{5}\] \[\therefore \] \[\frac{1}{2\sqrt{c}}=\frac{1}{5}\] Þ \[c=\frac{25}{4}=6.25\].You need to login to perform this action.
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