A) \[a>0\]
B) \[a\le \sqrt{3}\]
C) \[-\sqrt{3}\le a\le \sqrt{3}\]
D) None of these
Correct Answer: C
Solution :
[c] \[\frac{dy}{dx}=3{{x}^{2}}-2ax+1\] Given that \[\frac{dy}{dx}\ge 0\] or \[3{{x}^{2}}-2ax+1\ge 0\] for all \[x\] or \[D\le 0\] or \[4{{a}^{2}}-12\le 0\] or \[-\sqrt{3}\le a\le \sqrt{3}\]You need to login to perform this action.
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