A) One-one and onto
B) Onto but not one-one
C) One-one but not onto
D) Neither one-one nor onto
Correct Answer: B
Solution :
[b] \[f(x)=2{{x}^{3}}-15{{x}^{2}}+36x+1\] \[f'(x)=6{{x}^{2}}-30x+36=6(x-2)(x-3)\] Thus, \[f(x)\] is increasing in \[[0,2]\] and decreasing in \[[2,3]\]. Therefore \[f(x)\] is many-one. \[f(0)=1;f(2)=29;f(3)=28\] Range is \[[1,29]\]. Hence, \[f(x)\] is many-one-onto.You need to login to perform this action.
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