A) \[\frac{-{{E}_{a}}}{R}\]
B) \[\ell nA\]
C) \[\ell n\,K\]
D) \[lo{{g}_{10}}A\]
Correct Answer: B
Solution :
[b] According to Arrhenius equation, \[k=A.{{e}^{-{{E}_{a}}}}^{/RT}\] where k = rate constant or \[\ell nk=\ell nA-\frac{{{E}_{a}}}{RT}\] A = frequency factor \[{{E}_{a}}=\] Energy of activation.You need to login to perform this action.
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