A) log k versus log T will give a straight line with a slope as \[-25000\]
B) log k versus T will give a straight line with slope as 25000
C) log k versus 1/T will give a straight line with slope as \[-25000/R\]
D) log k versus 1/T will give a straight line
Correct Answer: C
Solution :
[c] \[k=1.2\times {{10}^{14}}{{e}^{-25000/RT}}{{\sec }^{-1}}\] or \[\log k=\log 1.2\times {{10}^{14}}-\frac{25000}{R}.\frac{1}{T}\] Equation of straight line \[slope=-\frac{25000}{R}\]You need to login to perform this action.
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