A) \[\sqrt{3}BM,s{{p}^{3}}{{d}^{2}}\]
B) \[\sqrt{3}BM,{{d}^{2}}s{{p}^{3}}\]
C) \[\sqrt{15}BM,s{{p}^{3}}{{d}^{2}}\]
D) \[\sqrt{15}BM,{{d}^{2}}s{{p}^{3}}\]
Correct Answer: C
Solution :
[c] Number of unpaired electrons = 3 \[{{\mu }_{eff}}=3.9BM\] type of hybridisation \[=s{{p}^{3}}{{d}^{2}}\]You need to login to perform this action.
You will be redirected in
3 sec