A) \[{{[MnB{{r}_{6}}]}^{4-}}\], octahedral
B) \[{{[MnB{{r}_{4}}]}^{2-}}\], square planar
C) \[{{[MnB{{r}_{4}}]}^{2-}}\], tetrahedral
D) \[{{[MnB{{r}_{5}}]}^{3-}}\], trigonal bipyramidal
Correct Answer: C
Solution :
[c] Magnetic moment, \[\sqrt{n(n+2)}=5.92\,B.M.\] \[\Rightarrow n\] (unpaired electrons) = 5 \[s{{p}^{3}}\] hybridization (tetrahedral)You need to login to perform this action.
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