A) \[8\times {{10}^{-15}}C\]
B) \[4\times {{10}^{-14}}C\]
C) \[12\times {{10}^{-14}}C\]
D) \[16\times {{10}^{-14}}C\]
Correct Answer: A
Solution :
[a] Number of emitted electrons \[=\frac{{{10}^{12}}\times 2\times {{10}^{-4}}\times 25}{{{10}^{5}}}=5\times {{10}^{4}}\text{ electrons}\] \[\text{q=+ne=}8\times {{10}^{-15}}C\]You need to login to perform this action.
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