A) the threshold frequency for sodium will be less than that for aluminum
B) the threshold frequency for sodium will be more than that of aluminum
C) both sodium and aluminum will have the same threshold frequency
D) none of the above
Correct Answer: A
Solution :
[a] As work function \[W=h{{v}_{0}},\], where \[{{v}_{0}}\] is the threshold frequency. Greater the work function, greater is the threshold frequency. Therefore, the threshold frequency of sodium will be lesser than that for aluminum.You need to login to perform this action.
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