A) 0.01 N
B) 0.01 M
C) 0.02 M
D) 0.2 N
Correct Answer: A
Solution :
[a] By Faraday's Ist law of electrolysis, \[\frac{W}{E}=\frac{Q}{96500}\] (where Q= it = charge of ion) We know that no. of gram equivalent \[=\frac{W}{E}=\frac{it}{96500}=\frac{1\times 965}{96500}=\frac{1}{100}\] (where i = 1 A,\[t=16\times 60+5=965\text{ }sec.\]) Since, we know that Normality \[=\frac{No.of\,gram\,equivalent}{Volume\text{ }\left( in\text{ }litre \right)}=\frac{\frac{1}{100}}{1}=0.01N\]You need to login to perform this action.
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