A) Increasing \[\left[ C{{l}^{-}} \right]\]
B) Decreasing \[\left[ C{{l}^{-}} \right]\]
C) Increasing \[H{{g}_{2}}C{{l}_{2}}(s)\]
D) Decreasing \[Hg\left( l \right)\]
Correct Answer: B
Solution :
[b] \[E=E{}^\circ -\frac{0.0591}{2}\log \frac{1}{{{[C{{l}^{-}}]}^{2}}};as\,[C{{l}^{-}}]\downarrow ,E\uparrow \]You need to login to perform this action.
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