A) \[{{r}^{2}}\]
B) \[r\]
C) \[\frac{1}{r}\]
D) \[\frac{1}{{{r}^{2}}}\]
Correct Answer: B
Solution :
[b] \[\vec{E}=\frac{\partial v}{\partial x}\hat{i}+\frac{\partial v}{\partial y}\hat{j}\] \[\therefore |\vec{E}|=k\left( \sqrt{{{x}^{2}}+{{y}^{2}}} \right)=kr\] Given \[v=-kxy\text{ }E\propto r\] \[\therefore \vec{E}=ky\hat{i}+ky\hat{j}\]You need to login to perform this action.
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