A) 270 V
B) 300 V
C) Zero
D) 100 V
Correct Answer: A
Solution :
[a] Potential at the center O, \[V=k\frac{q}{r}\] \[V=k\left[ \frac{2\times {{10}^{-8}}}{1}+\frac{-2\times {{10}^{-8}}}{1}+\frac{-3\times {{10}^{-8}}}{1}+\frac{6\times {{10}^{-8}}}{1} \right]\]\[V=k\times 3\times {{10}^{-8}}=9\times {{10}^{9}}\times 3\times {{10}^{-8}}volt\] \[=27\times 10=270v\]You need to login to perform this action.
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