A) \[{{10}^{2}}atm\]
B) \[2\times {{10}^{2}}at{{m}^{-1}}\]
C) \[50\text{ }at{{m}^{2}}\]
D) \[5\times {{10}^{-3}}at{{m}^{2}}\]
Correct Answer: D
Solution :
[d] \[{{K}_{p}}=\frac{{{p}_{C{{H}_{3}}OH}}}{{{p}_{CO}}\times {{p}_{{{H}_{2}}}}}=\frac{2}{1\times {{(0.1)}^{2}}}=200;\] For reverse reaction \[\frac{1}{{{K}_{p}}}=\frac{1}{200}=5\times {{10}^{-3}}at{{m}^{2}}\]You need to login to perform this action.
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