A) 4.900joule
B) 2.450joule
C) 0.495 joule
D) 0.245 joule
Correct Answer: B
Solution :
[b] \[K=\frac{F}{x}=\frac{4\times 9.8}{2\times {{10}^{-2}}}=19.6\times {{10}^{2}}\] Work done \[=\frac{1}{2}19.6\times {{10}^{2}}\times {{(0.05)}^{2}}=2.45J\]You need to login to perform this action.
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