A) A
B) B
C) C
D) D
Correct Answer: C
Solution :
[c] We have, \[U=\frac{{{F}^{2}}}{2k}\] Where \[k=\frac{Yl}{A}=\frac{Yl}{\frac{1}{4}\pi {{d}^{2}}}\] \[\therefore \,\,\,U\propto \frac{{{d}^{2}}}{l}\]You need to login to perform this action.
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