A) 31:9
B) 50:9
C) 47:9
D) 8:9
Correct Answer: B
Solution :
[b] \[{{T}_{1}}-{{T}_{2}}=m{{\omega }_{0}}^{2}(2l)\] \[{{T}_{2}}=m{{\omega }_{0}}^{2}(3l)\] \[\therefore \,\,{{T}_{1}}=5m{{\omega }_{0}}^{2}l.\] \[\frac{Energy(A)}{Energy(B)}=\frac{{{(stress)}^{2}}_{A}volume\,A}{{{(stress)}^{2}}_{B}\,volume\,B}\] \[=\frac{{{(5)}^{2}}}{{{(3)}^{2}}}\times \left( \frac{A\times 2l}{A\times l} \right)=\frac{50}{9}\]You need to login to perform this action.
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