A) 6250J
B) 0.177J
C) 0.075 J
D) 0.150J
Correct Answer: C
Solution :
[c] \[e=\frac{\Delta Y}{\ell }=\frac{1\times {{10}^{-3}}}{4}\] \[u=\frac{{{e}^{2}}y}{2}={{\left( \frac{{{10}^{-3}}}{4} \right)}^{2}}\times \frac{2\times {{10}^{11}}}{2}=0.075J\]You need to login to perform this action.
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