A) \[\sqrt{\frac{1}{2}}\]
B) \[\sqrt{\frac{1}{2.5}}\]
C) \[\sqrt{\frac{1}{3}}\]
D) \[\sqrt{\frac{1}{5}}\]
Correct Answer: C
Solution :
\[\frac{\text{ }\!\!~\!\!\text{ Time of ascent}}{\text{Time of descent}}=\frac{\left( \frac{u}{g+a} \right)}{\frac{u}{\sqrt{\left( g+a \right)\left( g-a \right)}}}\] \[=\frac{\sqrt{\left( g+a \right)\left( g-a \right)}}{g+a}=\sqrt{\frac{\left( g-a \right)}{g+a}}\] \[=\sqrt{\frac{10-5}{10+5}}=\sqrt{\frac{5}{15}}=\sqrt{\frac{1}{3}}\]You need to login to perform this action.
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