A) 5g
B) g
C) 8g
D) 10g
Correct Answer: D
Solution :
As the time taken from D to A = 2 sec. And D\[\to A\to B\to C=10\text{ sec}\left( given \right).\] As ball goes from \[B\to C\text{ }(\text{u=0, t=4sec})\] \[{{v}_{c}}=0+4g.\] As it moves from C to D, \[\text{s=ut+}\frac{1}{2}\text{a}{{\text{t}}^{2}}\] \[s=4g\times 2+\frac{1}{2}g\times 4=10g.\]You need to login to perform this action.
You will be redirected in
3 sec