A) \[\frac{\pi }{3}\]
B) \[\frac{-\pi }{6}\]
C) \[\frac{\pi }{6}\]
D) \[\frac{-\pi }{3}\]
Correct Answer: B
Solution :
[b] \[{{v}_{1}}=\frac{d{{y}_{1}}}{dt}=0.1\times 100\pi \cos \left( 100\pi t+\frac{\pi }{3} \right)\] \[{{v}_{2}}=\frac{d{{y}_{2}}}{dt}=-0.1\pi \sin \pi t\] \[=0.1\pi \cos \left( \pi t+\frac{\pi }{2} \right)\] \[\therefore \,\,Phase\,diff.\,={{\phi }_{1}}-{{\phi }_{2}}=\frac{\pi }{3}-\frac{\pi }{2}=\frac{2\pi -3\pi }{6}=\frac{\pi }{6}\]You need to login to perform this action.
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