A) 0
B) \[2\pi /3\]
C) \[\pi \]
D) \[\pi /6\]
Correct Answer: B
Solution :
[b] Equation of S.H.M. is given by \[x=A\,\sin \,(\omega t+\delta )\] \[(\omega t+\delta )\] is called phase. When \[x=\frac{A}{2},\]then \[\sin (\omega t+\delta )=\frac{1}{2}\] \[\Rightarrow \,\omega t+\delta =\frac{\pi }{6}\] \[or\,\,{{\phi }_{1}}=\frac{\pi }{6}\] For second particle, \[{{\phi }_{2}}=\pi -\frac{\pi }{6}=\frac{5\pi }{6}\] \[\therefore \,\,\phi ={{\phi }_{2}}-{{\phi }_{1}}=\frac{4\pi }{6}=\frac{2\pi }{3}\]You need to login to perform this action.
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