A) \[1.00 M\]
B) \[2.00\text{ }M\]
C) \[2.50\text{ }M\]
D) \[4.00\text{ }M\]
Correct Answer: B
Solution :
[b] Given mass of solute (w) = 120 g mass of solvent (w) = 1000 g Mol. mass of solute = 60 g density of solution = 1.12 g/ mL From the given data, Mass of solution\[~=1000+120=1120\text{ }g\] \[\because d=\frac{Mol.mass}{V}or\,V=\frac{Mol.mass}{d}\] Volume of solution\[~V=\frac{1120}{1.12}=1000\text{ }mL\] or = 1 litre Now molarity \[\left( M \right)=\frac{W}{Mol.mass\times V(lit)}\] \[=\frac{120}{60\times 1}=2M\]You need to login to perform this action.
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