A) 40
B) 48
C) 62
D) 72
Correct Answer: D
Solution :
[d] Let mole fraction of \[{{O}_{2}}\] is \[x\] \[40=32\times x+80\left( 1-x \right)\] or \[x=5/6\] \[a:b=x:\left( 1-x \right)=\frac{5}{6}:\frac{1}{6}\] When ratio is changed \[{{M}_{mixture}}=32\times \frac{1}{60}+80\times \frac{5}{6}=72\]You need to login to perform this action.
You will be redirected in
3 sec