A) \[6.7m/{{s}^{2}}\]
B) \[10m/{{s}^{2}}\]
C) \[3.3m/{{s}^{2}}\]
D) None of these
Correct Answer: A
Solution :
[a] Let friction force = f \[F+f=ma\] ? (i) \[(F-f)R=I\alpha \] ? (ii) \[From\,\,\,e{{q}^{n}}s.\,(i)\,and\,(ii),\] \[2F=ma+\frac{I\alpha }{R}\] \[Use\,\alpha =\frac{a}{R}\] (for pure rolling) \[2F=ma+\frac{Ia}{{{R}^{2}}}\] \[40=4a+\frac{0.02a}{{{(0.1)}^{2}}};a=\frac{40}{6}=6.7m/{{s}^{2}}\]You need to login to perform this action.
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