A) \[\frac{H}{h}=2\]
B) \[\frac{H}{h}=3\]
C) \[\frac{H}{h}=4\]
D) \[\frac{H}{h}=5\]
Correct Answer: D
Solution :
[d] Velocity at the bottom and top of the circle is \[\sqrt{5gr}\]and\[\sqrt{gr}\].Therefore \[(1/2)M(5gr)=MgH\] And\[\text{(1}/2\text{)}M(gr)=MgH\].You need to login to perform this action.
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