A) \[\sqrt{2}:\sqrt{1.5}\]
B) \[\sqrt{1.4}:\sqrt{1.5}\]
C) \[\sqrt{1.5}:\sqrt{1.5}\]
D) \[\sqrt{1.5}:\sqrt{1.6}\]
Correct Answer: A
Solution :
[a] \[t=\frac{1}{\sin }\theta \sqrt{\frac{2h}{g}\left[ 1+\frac{{{K}^{2}}}{{{R}^{2}}} \right]}\Rightarrow t\propto \left( 1+\frac{{{K}^{2}}}{{{R}^{2}}} \right)\] \[so,\,\,\,{{t}_{1}}:{{t}_{2}}=\sqrt{2}:\sqrt{1.5}\]You need to login to perform this action.
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