A) 318
B) 31.8
C) 3.18
D) 0.318
Correct Answer: D
Solution :
[d] Thermal resistance \[R=/lKA\] Where / =20cm. & A(cylindrical rod) \[=\pi {{r}^{2}}=40\pi c{{m}^{2}}\] So\[R=\frac{20}{0.5\times 40\pi }=0.318\frac{cal}{\sec \,\,\times {}^\circ C}\]You need to login to perform this action.
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