A) 108 joule
B) 168 joule
C) 182 joule
D) 192 joule
Correct Answer: C
Solution :
[c] According to Stefan's Law, the rate of loss of heat is \[\frac{Q}{t}=\sigma A\left( T_{1}^{4}-T_{2}^{4} \right)\times e\] here \[\sigma =5.67\times {{10}^{-8}}/{{m}^{2}}\times sec.{{K}^{2}},\] \[{{\operatorname{T}}_{1}}=527+273=800K,\] \[{{\operatorname{T}}_{2}}=27+273=300K\And A=200\times l{{0}^{-\,4}}{{m}^{2}}\] So. \[\frac{Q}{t}=5.67\times {{10}^{-8}}\times 2\times l{{0}^{-2}}\] \[[{{(800)}^{4}}-{{(300)}^{4}}]\times 0.4\] \[\cong 182 joule\]You need to login to perform this action.
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