A) \[1.24J/m{}^\circ C\]
B) \[1.29J/m{}^\circ C\]
C) \[2.05J/m{}^\circ C\]
D) \[1.02J/m{}^\circ C\]
Correct Answer: A
Solution :
[a] \[\frac{dQ}{dt}=\frac{KA\left( 100-0 \right)}{1}=m\frac{dL}{dt},\] \[\frac{K\times 100\times 0.36}{0.1}=\frac{4.8\times 3.36\times {{10}^{5}}}{60\times 60}\] \[=1.24J/m/s/{}^\circ C\]You need to login to perform this action.
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