A) 50 K
B) 12.5 K
C) 25 K
D) 60 K
Correct Answer: C
Solution :
[c] Let T be temperature of the junction Here, \[{{\operatorname{K}}_{A}}=2{{K}_{B}},\] \[\operatorname{T}-{{T}_{B}}=50K\] At the steady state, \[{{H}_{A}}={{H}_{B}}\] \[\therefore \frac{{{K}_{A}}A\left( {{T}_{A}}-T \right)}{L}=\frac{{{K}_{B}}A\left( {{T}_{B}}-T \right)}{L}\] \[2{{K}_{B}}\left( {{T}_{A}}-T \right)={{K}_{B}}\left( T-{{T}_{B}} \right)\] \[{{T}_{A}}-T=\frac{T-{{T}_{B}}}{2}=\frac{50K}{2}=25K\]You need to login to perform this action.
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