A) 3 : 1
B) 1 : 3
C) 4 : 1
D) 1 : 4
Correct Answer: C
Solution :
Let x mole of KOH be neutralized by the strong acid HA. Then, moles neutralized by \[HB=1-x\] Hence, \[-13.7\times x+\left( -12.7 \right)\times \left( 1-x \right)=-13.5\] \[\Rightarrow x=0.8;\,\,\,\,\,\,\frac{x}{1-x}=\frac{0.8}{0.2}=\frac{4}{1}4:1\]You need to login to perform this action.
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