A) 1.30
B) 1.50
C) 1.70
D) 2
Correct Answer: B
Solution :
\[T\propto \frac{1}{\sqrt{V}};T{{V}^{1/2}}=\]constant For adiabatic process, \[T{{V}^{\gamma -1}}\] = constant \[\therefore \gamma -1=\frac{1}{2},\,\gamma =\frac{3}{2}\]You need to login to perform this action.
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