A) 2
B) 3
C) 4
D) more than 4
Correct Answer: A
Solution :
[a] Angular width\[=\frac{\lambda }{d}={{10}^{-3}}\] (given) \[\therefore \] No. of fringes within \[0.12{}^\circ \] will be \[n=\frac{0.12\times 2\pi }{360\times {{10}^{-3}}}\cong \left[ 2.09 \right]\] \[\therefore \] The number of bright spots will be twoYou need to login to perform this action.
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