A) \[{{d}^{2}}/D,\,{{d}^{2}}/2D,\,{{d}^{2}}/3D\]
B) \[{{d}^{2}}/D,\,{{d}^{2}}/3D,\,{{d}^{2}}/5D\]
C) \[{{d}^{2}}/2D,\,{{d}^{2}}/4D,\,{{d}^{2}}/6D\]
D) None of these
Correct Answer: C
Solution :
[c] \[{{S}_{2}}P-{{S}_{1}}P=\frac{dy}{D}=\frac{d\times (d/2)}{D}=\frac{{{d}^{2}}}{2D}\] \[\frac{{{d}^{2}}}{2D}=n\lambda \] \[\lambda =\frac{d}{2nD}\], n=1, 2, ??.. \[\lambda =\frac{{{d}^{2}}}{2D},\,\frac{{{d}^{2}}}{4D},\frac{{{d}^{2}}}{6D}\]You need to login to perform this action.
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