A) \[6\times {{10}^{-6}}m\]
B) \[6.6\times {{10}^{-6}}m\]
C) \[3.318\times {{10}^{-7}}m\]
D) \[3.144\times {{10}^{-7}}m\]
Correct Answer: A
Solution :
[a] Path difference between first and \[{{11}^{th}}\] bright fringe \[{{S}_{1}}B\] (10 bright fringes) \[=10\lambda \] \[=10\times (6000\times {{10}^{-7}})m=6\times {{10}^{-6}}m\]You need to login to perform this action.
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