A) \[\frac{27\,{{I}_{0}}}{9}\]
B) \[\frac{25\,{{I}_{0}}}{9}\]
C) \[\frac{17\,{{I}_{0}}}{9}\]
D) \[\frac{10\,{{I}_{0}}}{9}\]
Correct Answer: D
Solution :
[d] \[{{E}_{1}}={{I}_{0}}=\frac{L}{{{d}^{2}}}\], without mirror And \[{{E}_{2}}=\frac{L}{{{d}^{2}}}+\frac{L}{{{(3d)}^{2}}}=\frac{L}{{{d}^{2}}}\left[ 1+\frac{1}{9} \right]=\frac{10{{I}_{0}}}{9}\] with mirror.You need to login to perform this action.
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